A router receives an EIGRP route advertisement with an advertised distance of 1200 for a prefix whose current feasible distance is 1500. According to the feasibility condition, what is true about this route?
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Correct answer: It qualifies as a feasible successor because the advertised distance is less than the feasible distance.
Why this is the answer
The feasibility condition states that a route can be considered a feasible successor if its advertised distance (AD) is strictly less than the feasible distance (FD) of the current successor route. In this scenario, the advertised distance (1200) is less than the feasible distance (1500), so the route qualifies as a feasible successor. This allows the router to use this path as a backup without recalculating the topology if the primary successor fails. The AD does not need to equal the FD, and an AD of zero is not a requirement. The route will not be installed immediately as the successor unless it also has the lowest FD among all paths.
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