Increasing an AP's transmit power from 25 mW to 100 mW produces what change in dBm?

Doubling the power in mW results in a 3 dBm increase. Since the power increased from 25 mW to 100 mW, it doubled twice (25 mW to 50 mW, then 50 mW to 100 mW). Each doubling adds 3 dBm, so 3 dBm + 3 dBm = 6 dBm. Alternatively, you can use the formula: dBm = 10 log10 (Power in mW). For 25 mW, dBm = 10 log10(25) ≈ 14 dBm. For 100 mW, dBm = 10 log10(100) = 20 dBm. The difference is 20 dBm - 14 dBm = 6 dBm. 14 dBm and 20 dBm are the absolute dBm values, not the change. 17 dBm is incorrect as it represents an approximate tripling of power, not quadrupling.